Optimal. Leaf size=249 \[ \frac{2 a^2 (a+b x) (3 A b-5 a B) \log (a+b x)}{b^6 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{3 a x (a+b x) (A b-2 a B)}{b^5 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{x^2 (a+b x) (A b-3 a B)}{2 b^4 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{B x^3 (a+b x)}{3 b^3 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{a^4 (A b-a B)}{2 b^6 (a+b x) \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{a^3 (4 A b-5 a B)}{b^6 \sqrt{a^2+2 a b x+b^2 x^2}} \]
[Out]
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Rubi [A] time = 0.472946, antiderivative size = 249, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.069 \[ \frac{2 a^2 (a+b x) (3 A b-5 a B) \log (a+b x)}{b^6 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{3 a x (a+b x) (A b-2 a B)}{b^5 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{x^2 (a+b x) (A b-3 a B)}{2 b^4 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{B x^3 (a+b x)}{3 b^3 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{a^4 (A b-a B)}{2 b^6 (a+b x) \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{a^3 (4 A b-5 a B)}{b^6 \sqrt{a^2+2 a b x+b^2 x^2}} \]
Antiderivative was successfully verified.
[In] Int[(x^4*(A + B*x))/(a^2 + 2*a*b*x + b^2*x^2)^(3/2),x]
[Out]
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Rubi in Sympy [A] time = 34.0777, size = 260, normalized size = 1.04 \[ \frac{B x^{5} \left (2 a + 2 b x\right )}{6 b \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}}} + \frac{2 a^{2} \left (a + b x\right ) \left (3 A b - 5 B a\right ) \log{\left (a + b x \right )}}{b^{6} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}} - \frac{2 a \left (3 A b - 5 B a\right ) \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}}{b^{6}} - \frac{x^{4} \left (2 a + 2 b x\right ) \left (3 A b - 5 B a\right )}{12 b^{2} \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}}} - \frac{2 x^{3} \left (3 A b - 5 B a\right )}{3 b^{3} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}} + \frac{x^{2} \left (2 a + 2 b x\right ) \left (3 A b - 5 B a\right )}{2 b^{4} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x**4*(B*x+A)/(b**2*x**2+2*a*b*x+a**2)**(3/2),x)
[Out]
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Mathematica [A] time = 0.133437, size = 140, normalized size = 0.56 \[ \frac{-27 a^5 B+3 a^4 b (7 A+2 B x)+3 a^3 b^2 x (2 A+21 B x)+a^2 b^3 x^2 (20 B x-33 A)-12 a^2 (a+b x)^2 (5 a B-3 A b) \log (a+b x)-a b^4 x^3 (12 A+5 B x)+b^5 x^4 (3 A+2 B x)}{6 b^6 (a+b x) \sqrt{(a+b x)^2}} \]
Antiderivative was successfully verified.
[In] Integrate[(x^4*(A + B*x))/(a^2 + 2*a*b*x + b^2*x^2)^(3/2),x]
[Out]
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Maple [A] time = 0.023, size = 217, normalized size = 0.9 \[{\frac{ \left ( 2\,B{b}^{5}{x}^{5}+3\,A{x}^{4}{b}^{5}-5\,B{x}^{4}a{b}^{4}+36\,A\ln \left ( bx+a \right ){x}^{2}{a}^{2}{b}^{3}-12\,A{x}^{3}a{b}^{4}-60\,B\ln \left ( bx+a \right ){x}^{2}{a}^{3}{b}^{2}+20\,B{x}^{3}{a}^{2}{b}^{3}+72\,A\ln \left ( bx+a \right ) x{a}^{3}{b}^{2}-33\,A{x}^{2}{a}^{2}{b}^{3}-120\,B\ln \left ( bx+a \right ) x{a}^{4}b+63\,B{x}^{2}{a}^{3}{b}^{2}+36\,A\ln \left ( bx+a \right ){a}^{4}b+6\,Ax{a}^{3}{b}^{2}-60\,B\ln \left ( bx+a \right ){a}^{5}+6\,Bx{a}^{4}b+21\,A{a}^{4}b-27\,B{a}^{5} \right ) \left ( bx+a \right ) }{6\,{b}^{6}} \left ( \left ( bx+a \right ) ^{2} \right ) ^{-{\frac{3}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x^4*(B*x+A)/(b^2*x^2+2*a*b*x+a^2)^(3/2),x)
[Out]
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Maxima [A] time = 0.716908, size = 508, normalized size = 2.04 \[ \frac{B x^{4}}{3 \, \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2}} b^{2}} - \frac{7 \, B a x^{3}}{6 \, \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2}} b^{3}} + \frac{A x^{3}}{2 \, \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2}} b^{2}} + \frac{9 \, B a^{2} x^{2}}{2 \, \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2}} b^{4}} - \frac{5 \, A a x^{2}}{2 \, \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2}} b^{3}} - \frac{10 \, B a^{3} \log \left (x + \frac{a}{b}\right )}{{\left (b^{2}\right )}^{\frac{3}{2}} b^{3}} + \frac{6 \, A a^{2} \log \left (x + \frac{a}{b}\right )}{{\left (b^{2}\right )}^{\frac{3}{2}} b^{2}} + \frac{9 \, A a^{4}}{{\left (b^{2}\right )}^{\frac{7}{2}}{\left (x + \frac{a}{b}\right )}^{2}} - \frac{15 \, B a^{5}}{{\left (b^{2}\right )}^{\frac{7}{2}} b{\left (x + \frac{a}{b}\right )}^{2}} - \frac{20 \, B a^{4} x}{{\left (b^{2}\right )}^{\frac{5}{2}} b^{2}{\left (x + \frac{a}{b}\right )}^{2}} + \frac{12 \, A a^{3} x}{{\left (b^{2}\right )}^{\frac{5}{2}} b{\left (x + \frac{a}{b}\right )}^{2}} + \frac{9 \, B a^{4}}{\sqrt{b^{2} x^{2} + 2 \, a b x + a^{2}} b^{6}} - \frac{5 \, A a^{3}}{\sqrt{b^{2} x^{2} + 2 \, a b x + a^{2}} b^{5}} - \frac{9 \, B a^{5}}{2 \,{\left (b^{2}\right )}^{\frac{3}{2}} b^{5}{\left (x + \frac{a}{b}\right )}^{2}} + \frac{5 \, A a^{4}}{2 \,{\left (b^{2}\right )}^{\frac{3}{2}} b^{4}{\left (x + \frac{a}{b}\right )}^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*x^4/(b^2*x^2 + 2*a*b*x + a^2)^(3/2),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.299069, size = 266, normalized size = 1.07 \[ \frac{2 \, B b^{5} x^{5} - 27 \, B a^{5} + 21 \, A a^{4} b -{\left (5 \, B a b^{4} - 3 \, A b^{5}\right )} x^{4} + 4 \,{\left (5 \, B a^{2} b^{3} - 3 \, A a b^{4}\right )} x^{3} + 3 \,{\left (21 \, B a^{3} b^{2} - 11 \, A a^{2} b^{3}\right )} x^{2} + 6 \,{\left (B a^{4} b + A a^{3} b^{2}\right )} x - 12 \,{\left (5 \, B a^{5} - 3 \, A a^{4} b +{\left (5 \, B a^{3} b^{2} - 3 \, A a^{2} b^{3}\right )} x^{2} + 2 \,{\left (5 \, B a^{4} b - 3 \, A a^{3} b^{2}\right )} x\right )} \log \left (b x + a\right )}{6 \,{\left (b^{8} x^{2} + 2 \, a b^{7} x + a^{2} b^{6}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*x^4/(b^2*x^2 + 2*a*b*x + a^2)^(3/2),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{x^{4} \left (A + B x\right )}{\left (\left (a + b x\right )^{2}\right )^{\frac{3}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x**4*(B*x+A)/(b**2*x**2+2*a*b*x+a**2)**(3/2),x)
[Out]
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GIAC/XCAS [A] time = 0.569253, size = 4, normalized size = 0.02 \[ \mathit{sage}_{0} x \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*x^4/(b^2*x^2 + 2*a*b*x + a^2)^(3/2),x, algorithm="giac")
[Out]